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| 1. |
Find the values of k so that (x-1) is a factor of k2x2 - 2kx - 3 |
| Answer» This is the easiest sum you can get strucked very easily.Answer:-Since (x-1) is a factor of k²x² - 2kx - 3 so, we can say x-1 = 0=> x = 1Using x=1 in p(x) = k²x² - 2kx - 3p(1) => k²(1)² - 2k(1) - 3 = 0=> k² - 2k - 3 = 0=> k² - 3k +k -3 = 0=> (k-3)(k+1) = 0=> k = 3, -1 | |