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Find the values of x and y which satisfy the following equations (x, y ∈ R),If x(1 + 3i) + y(2 – i) – 5 + i3= 0, find x + y |
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Answer» x(1 + 3i) + y(2 – i) – 5 + i3 = 0 x + 3xi + 2y – yi – 5 – i = 0 ……[∵ i3 = -i] (x + 2y – 5) + (3x – y – 1)i = 0 + 0i Equating real and imaginary parts, we get x + 2y – 5 = 0 …..(i) and 3x – y – 1 = 0 ……(ii) Equation (i) + equation (ii) × 2 gives 7x – 7 = 0 7x = 1 ∴ x = 1 Substituting x = 1 in (i), we get 1 + 2y – 5 = 0 2y = 4 y = 2 ∴ x = 1 and y = 2 ∴ x + y = 1 + 2 = 3 |
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