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Find the values of x and y which satisfy the following equations (x, y ∈ R)(x + 2y) + (2x – 3y)i + 4i = 5 |
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Answer» (x + 2y) + (2x – 3y)i + 4i = 5 (x + 2y) + (2x – 3y)i = 5 – 4i Equating real and imaginary parts, we get x + 2y = 5 ……(i) and 2x – 3y = -4 …..(ii) Equation (i) x 2 – equation (ii) gives 7y = 14 ∴ y = 2 Substituting y = 2 in (i), we get x + 2(2) = 5 x + 4 = 5 ∴ x = 1 ∴ x = 1 and y = 2 Check: For x = 1 and y = 2 Consider, L.H.S. = (x + 2y) + (2x – 3y)i + 4i = (1 + 4) + (2 – 6)i + 4i = 5 – 4i + 4i = 5 = R.H.S. |
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