1.

Find the zeroes of integers between 10 and 500 which are divisible by 7 ?

Answer» So, the sum of integers between 10 and 500 is 17885.
AP are : 14 , 21 , 28 ......497 . So, a= 14 , Tn = 497 , d= 7 . Now, Tn = a + (n-1) d => 497 = 14 +(n-1) 7 => n= 70 . Sn = n/2 ( Tn + a) => Sn = 70/2 ( 497+14) => Sn = 35× 511 => Sn = 17885 .


Discussion

No Comment Found