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                                    Find the zeroes of the polynomial 4X^2+3X+7 ????? | 
                            
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Answer» 4x^2+3x+7=4x^2+7x-4x+7=4x(x+7/4)-4(x+7/4)=(4x-4) or (x+7/4)=0=x=1 or x=-7/4 1,-7/4 4x^2 +3x+7(4x^2+4x)+(7x+7)4x(x+1)+7(x+1)(4x+7)(x+1)  | 
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