Find the zeroes of the polynomial 6x2-7x-3

1.	Find the zeroes of the polynomial 6x2-7x-3
Answer» =6x²-7x-3=6x²+2x-9x-3=2x(3x+1)-3(3x+1)=(2x-3)(3x+1)⇒2x-3=0 ⇒3x+1=0⇒x=3/2 ⇒x= - 1/3α=3/2 ,β= - 1/3

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