Find the zeroes of the polynomial 7y2-11/3y-2/3

1.	Find the zeroes of the polynomial 7y2-11/3y-2/3
Answer» 7y2\xa0-\xa0{tex}\\frac { 11 } { 3 } y - \\frac { 2 } { 3 }{/tex}=\xa0{tex}\\frac 13{/tex}(21y2\xa0- 11y - 2)=\xa0{tex}\\frac 13{/tex}(21y2\xa0- 14y + 3y - 2)=\xa0{tex}\\frac 13{/tex}[7y(3y - 2) + 1(3y - 2)]=\xa0{tex}\\frac 13{/tex}(3y - 2)(7y + 1){tex}\\Rightarrow y = \\frac { 2 } { 3 } , \\frac { - 1 } { 7 }{/tex}\xa0are zeroes of the polynomial.

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