Find the zeroes of the polynomial x²-4x+8

1.	Find the zeroes of the polynomial x²-4x+8
Answer» {tex}\\huge {=>\\ x = {-b \\pm \\sqrt{b^2-4ac} \\over 2a}}\\\\\\huge {=>\\ x = {-(-2) \\pm \\sqrt{(-2)^2-4(1)(8)} \\over 2\\times 1}}\\\\\\huge {=>\\ x = {2 \\pm \\sqrt{4-32} \\over 2}}\\\\\\huge {=>\\ x = {2 \\pm \\sqrt{-28} \\over 2}}\\\\\\huge {=>\\ x = {1 \\pm \\sqrt{-7} }}\\\\\\text{Since,} \\huge{ {b^2-4ac}}\\ is\\ smaller\\ than\\ 0.\\ Thus,\\ no\\ real\\ roots\\ or\\ zeros\\ exist.{/tex} U can use quadratic formula ie - b +- √b^2-4ac/2a

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