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Find the zerors of the given polynomial X^2+3X+2 |
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Answer» 2x²+3x+2=02x²+4x-1x+2=02x(x+2)-1(x+2)=0(X+2) (2x-1)=0X=-2 & x=1/2 X^2+x+2x+2x(x+1)+2(x+1)(x+1)(x+2)x = -1,-2 |
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