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| 1. |
Find the zeros of 4 x^2 - 4 x + 1 |
| Answer» For zeroes -4x² - 4x +1 = 04x² - 2x - 2x + 1 = 02x(2x - 1) - 1(2x - 1) = 0(2x - 1)(2x - 1) = 02x - 1 = 0 or 2x - 1 = 0x = 1/2 or x = 1/2Hence, the zeroes are 1/2,1/2. | |