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Find the zeros of the polynomial 6?2 − 3 − 7? and verify the relationship between the zeros and

Answer» =6x²-7x-3=6x²+2x-9x-3=2x(3x+1)-3(3x+1)=(2x-3)(3x+1)⇒2x-3=0 or ⇒3x+1=0⇒x=3/2 or ⇒ x= - 1/3α=3/2 ,β= - 1/3⇒α+β= -b/a⇒3/2+(-1/3)= - (-3)/6⇒3/2-1/3=1/2⇒7/6 =1/2\xa0⇒αβ=c/a\xa0⇒\xa03/2(-1/3)= -7/6⇒-1/2= -7/6\xa0⇒1/2=7/6


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