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| 1. |
Find the zeros of the polynomial x*x+x-p(p+1). |
| Answer» We have,{tex}f(x) = x^2 + x - p(p + 1){/tex}{tex}= x^2 + (p + 1)x - px - p(p + 1) {/tex}[As x =(p + 1)x - px ]{tex}= x[ x + (p + 1)] - p[ x + (p + 1)]{/tex}{tex}= ( x - p)[x + (p + 1)]{/tex}{tex}{/tex}\xa0Now, f(x) = 0{tex}\\Rightarrow{/tex}\xa0( x - p)[x + (p + 1)] = 0{tex}\\Rightarrow{/tex}\xa0x - p = 0 or x + (p +1) = 0{tex}\\Rightarrow{/tex}\xa0x = p or x = -(p + 1)Thus, the required zeros of f(x) are p and -(p + 1). | |