Find the zeros of the quadratic polynomial 8x²-4

1.	Find the zeros of the quadratic polynomial 8x²-4
Answer» 8x²-4 = 04 (2x2 - 1) = 04 (√2 x - 1) ( √2x + 1) = 0√2 x - 1 = 0 and √2 x + 1 = 0x = 1/√2 and x = -1/√

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