InterviewSolution
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InterviewSolution
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Find the zeros of x2-2x-8 |
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Answer» x2 - 2x - 8=x2 - (4 - 2)x - 8=x2 - 4x + 2x - 8=x(x - 4) + 2(x - 4)=(x - 4)(x + 2)=0 (x - 4)=0 or (x + 2)=0 x=4 x = -2So zeros are 4 and -2 x2-2x-8= x2\xa0- 4x + 2x - 8= x( x - 4) + 2 (x - 4)= ( x + 2) ( x - 4) x2 - 2x - 8 = 0= x2 - 4x + 2x - 8 = 0= x(x - 4) + 2(x - 4) = 0= (x + 2) (x - 4) = 0So zeros are -2 and 4 x2-2x-8= x2 - 4x + 2x - 8= x( x - 4) + 2 (x - 4)= ( x + 2) ( x - 4) |
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