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find to ratio in which the line segment joining the point (-3,10)and (6,-8) is divided by (-1,6)

Answer» Let (-1, 6) divides line segment joining the points (-3, 10) and(6, -8) in k:1.Using Section formula, we get{tex} - 1 = \\frac{{( - 3) \\times 1 + 6 \\times k}}{{k + 1}}{/tex}\xa0{tex}4 \\Rightarrow - k - 1 = ( - 3 + 6k){/tex}⇒ −7k = −2 ⇒ k= {tex}\\frac{2}{7}{/tex}Therefore, the ratio is {tex}\\frac{2}{7}:1{/tex}\xa0which is equivalent to 2:7.Therefore, (-1, 6) divides line segment joining the points (-3, 10) and (6, -8) in 2:7.


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