Find two consecutive multiples of 3 whose products is 648.

1.	Find two consecutive multiples of 3 whose products is 648.
Answer» Let two consecutive multiples of 3 be x and (x+3)As per given conditionx (x+3) = 648⇒ x² + 3x = 648⇒ x² + 3x -648 = 0⇒ x² + 27x - 24x -648 = 0⇒ x ( x + 27 ) -24 ( x +27)⇒ ( x - 24) ( x + 27)⇒ x = 24 and x = -27so, we take x = 24.Required multiples of 3⇒ x = 24⇒ x +3 = 24+3 = 27.\xa0

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