find two consecutive positive integers,sum of whose squares is 365

1.	find two consecutive positive integers,sum of whose squares is 365
Answer» let the no. be x and x+1 then we have x²+(x+1)²=365\xa02x²+2x-364=0x²+x-182=0x²+14x-13x-182=0(x+14)(x-13)=0That gives x=13 Avoiding negative valueone number is 13 and other one 14.\xa0

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