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Find two consecutive positive intiger whose sum is 21 and products is 110 |
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Answer» Formula Let\xa0first number = xsince this no are consecutive sosecond number = x+1\xa0now according to question\xa0x (x+1) = 110\xa0x² + x = 110\xa0x² + x - 110 = 0\xa0by using factorization method\xa0x² + 11x - 10x -110 = 0x(x+11) -10(x+10) = 0(x+11) (x-10) = 0∵ x = -11 and x = 10The two numbers would be 10 and 11.10 x 11 = 11010 + 11 = 21 |
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