Saved Bookmarks
| 1. |
Find value of @ for which (@ - 12)x2+(@-12)x+2=0 has equal zeroes and ........ @= alpha |
| Answer» We have, (k- 12 )x2 + 2(k - 12)x + 2 = 0.\xa0a = k - 12,b = 2(k - 12) and c = 2.The given equation will have equal roots, if{tex}\\therefore{/tex}\xa0D = b2 - 4ac = 0{tex}\\Rightarrow{/tex}\xa04(k\xa0- 12)2 - 4 (k - 12){tex}\\times{/tex} 2 = 0{tex}\\Rightarrow{/tex}4(k- 12) [(k\xa0- 12) - 2]\xa0= 0{tex}\\Rightarrow{/tex}4(k\xa0- 12)(k\xa0- 14) = 0{tex}\\Rightarrow{/tex}4(k\xa0- 12) (k - 14) = 0 {tex}\\Rightarrow{/tex}\xa0k - 12 = 0 or, k - 14 = 0 {tex}\\Rightarrow{/tex}\xa0k\xa0= 12 or, k = 14 | |