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Find values of k if area of triangle is 4 sq. units and vertices are (i) `(k, 0), (4, 0), (0, 2)`(ii) `(–2, 0), (0, 4), (0, k)`

Answer» Area of a triangle is given by,
`Ar = 1/2|[x_1,y_1,1],[x_2,y_2,1],[x_3,y_3,1]|`
So, putting the given vertices,
`Ar = 1/2|[-2,0,1],[0,4,1],[0,k,1]|`
As Area is `4` square units,
`So, 1/2|[-2,0,1],[0,4,1],[0,k,1]| = 4`
`=>|[-2,0,1],[0,4,1],[0,k,1]| = 8`
`=>-2(4-k)-0+1(0,0) = +-8`
`=>-8+2k = +-8`
`=>2k = 16 and 2k = 0`
`=>k = 8 and k =0`


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