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Find x, if \(\begin{vmatrix}x - 1& x - 2\\[0.3em]x & x - 3\end{vmatrix} = 0\) |
Answer» \(\begin{vmatrix}x - 1& x - 2\\[0.3em]x & x - 3\end{vmatrix} = 0\) ⇒ (x – 1) (x – 3) – x(x – 2) = 0 ⇒ x2 – 3x – x + 3 – x2 + 2x = 0 ⇒ -2x + 3 = 0 ⇒ – 2x = -3 So, x = 3/2 |
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