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find zero of the polynomial x+7x+12

Answer» The zeros of f(x) are given by f(x) = 0{tex} \\Rightarrow {/tex}x2\xa0+ 7x + 12 = 0{tex}\\Rightarrow {/tex}(x + 4)(x + 3) = 0{tex}\\Rightarrow {/tex}\xa0x + 4 = 0 or, x + 3 = 0{tex}\\Rightarrow {/tex}\xa0x = -4 or, -3Thus, the zeroes\xa0of f(x) =\xa0x2 +7x + 12 are\xa0{tex}\\alpha = - 4 \\text { and } \\beta = - 3{/tex}


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