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Find zeros of √3x2 +10x +7√3 |
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Answer» \xa0√ 3x2 + 10x + 7\xa0√ 3 √ 3x2 + 3x + 7x + 7\xa0√ 3 =0 √ 3x( x + √ 3) + 7 ( x + √ 3) = 0\xa0( x + √ 3) ( √ 3x + 7) = 0x + √ 3 = 0 and √ 3x + 7 = 0x = - √3 and x = -7/\xa0√3 X=-√3,. -7/√3 This equation does not have any real roots as its discriminant is less than zero X=-√3 and x=-7/√3 |
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