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| 1. |
Find zeros of tsq-15 |
| Answer» First, write the equation,t2\xa0- 15 = 0Now, we shift the (-15) to RHS,t2 = 15So, t = - {tex}\\sqrt {15}{/tex} = -3.87 or + {tex}\\sqrt {15}{/tex} = + 3.87 | |