1.

Five men A, B, C, D and E can do a piece of work in 20, 10, 30, 40 and 50 days respectively. A, B, and C started the work and they work for 2 days after which A and B left the work and D joins the work. D and C work another 3 days together after which C leaves and E joins the work. Find in how many days E and D completed the rest of the work.1). 10.2 days2). 12.64 days3). 20.5 days4). 11.48 days

Answer»

Let the total units of WORK be 600

 

DAYS TO COMPLETE THE WORK

Per day capacity

A

20

30 units

B

10

60 units

C

30

20 units

D

40

15 units

E

50

12 units

 

A, B, and C started the work and they work for 2 days

⇒ Number of units PRODUCED in TWO days by A, B and C = (30 + 60 + 20) × 2 = 220 units

Then A and B left the work and D and C work another 3 days together

⇒ Number of units produced in 3 days by D and C = (15 + 20) × 3 = 35 × 3 = 105 units

⇒ Work left for D and E = 600 – 220 – 105 = 275 units

∴ D and E will complete REST of the task in 275/(15 + 12) days = 10.2 days


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