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Five men A, B, C, D and E can do a piece of work in 20, 10, 30, 40 and 50 days respectively. A, B, and C started the work and they work for 2 days after which A and B left the work and D joins the work. D and C work another 3 days together after which C leaves and E joins the work. Find in how many days E and D completed the rest of the work.1). 10.2 days2). 12.64 days3). 20.5 days4). 11.48 days |
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Answer» Let the total units of WORK be 600
A, B, and C started the work and they work for 2 days ⇒ Number of units PRODUCED in TWO days by A, B and C = (30 + 60 + 20) × 2 = 220 units Then A and B left the work and D and C work another 3 days together ⇒ Number of units produced in 3 days by D and C = (15 + 20) × 3 = 35 × 3 = 105 units ⇒ Work left for D and E = 600 – 220 – 105 = 275 units ∴ D and E will complete REST of the task in 275/(15 + 12) days = 10.2 days |
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