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for any positive integer n prove that n cube minus n is divisible by 6

Answer» Take A as a postive integer and b=6 for some integer qThen , A can be 6q, 6q+1,6q +2, 6q +3 ,6q +4, 6q +5 Now , put each value in n3-n And you find that after solving each is divisible by 6 so , n3-n is divisible by 6


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