For how many integers n is √9 - ( n + 2 )^2.

1.	For how many integers n is √9 - ( n + 2 )^2.
Answer» 9 -(n+2)^2=[3^2-(n+2)^2)=using identity a^2-b^2=(a+b)(a-b)=(3-n+2)(3+n-2)=n=-5,1

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