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For θ=30°, verify that : Sin2θ=2tanθ/1+tan²θ |
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Answer» From RHS ≈2tan theta /1+tan² theta≈2tan30/1+tan²30≈2×1/√3/1+(1/√3)²≈2/√3/4/3≈6/4√3≈6/√3/12≈√3/2From LHSSin2 thetaSin2(30)Sin60√3/2 LHS =RHSHence proved sin2*30°=2tan30°/1+tan30°*tan30° |
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