For the equilibrium `:` `I: C_(6)H_(5)COOH+H_(2)OhArr C_(6)H_(5)COO^(-)+H_(3)O^(+),K_(1)=6.30xx10^(-5)` `II: C_(6)H_(5)COOH+OH^(-)hArrC_(6)H_(5)COO^(-)+H_(2)O, K_(2)=6.30xx10^(9)` `III: H_(2)O+H_(2)OhArr H_(3)O^(+)+OH^(-), K_(3)=?` `K_(3)` using above equilibria is` :`A. `(6.30)^(2)xx10^(4)`B. `1.0xx10^(-14)`C. `1xx10^(14)`D. `(6.30)^(-2)xx10^(-4)`

For the equilibrium `:` `I: C_(6)H_(5)COOH+H_(2)OhArr C_(6)H_(5)COO^(-

1.	For the equilibrium `:` `I: C_(6)H_(5)COOH+H_(2)OhArr C_(6)H_(5)COO^(-)+H_(3)O^(+),K_(1)=6.30xx10^(-5)` `II: C_(6)H_(5)COOH+OH^(-)hArrC_(6)H_(5)COO^(-)+H_(2)O, K_(2)=6.30xx10^(9)` `III: H_(2)O+H_(2)OhArr H_(3)O^(+)+OH^(-), K_(3)=?` `K_(3)` using above equilibria is` :`A. `(6.30)^(2)xx10^(4)`B. `1.0xx10^(-14)`C. `1xx10^(14)`D. `(6.30)^(-2)xx10^(-4)`
Answer» Correct Answer - B `C_(6)H_(5)COOH+H_(2)O hArr C_(6)H_(5)COO^(-)+H_(3)O^(+),K=K_(1)` `C_(6)H_(5)COO^(-)+H_(2)O hArr C_(6)H_(5)COOH+OH^(-), K=(1)/(K_(2))` Adding, we get `H_(2)O +H_(2)O hArr H_(3)O^(+)+OH^(-), K_(3)=(K_(1))/(K_(2))` `:. K_(3)=(6.30xx10^(-5))/(6.30xx10^(9))=10^(-14)`

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