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For the following equilibrium `N_(2)O_(4)(g)hArr 2NO_(2)(g)` `K_(p)` is found to be equal to `K_(c)`. This is attained when `:`A. `T=1K`B. `T=12.18K`C. `T=27.3K`D. `T=273K` |
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Answer» Correct Answer - B `K_(p)=K_(c)(RT)^(Deltan)` Here, `K_(p)=K_(c),Deltan=2-1=1` `:. (RT)^(Deltan)=1` `(0.0821xxT)=1` `T=(1)/(0.0821)=(10000)/(821)=12.18K` |
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