For the same objective, the ratio of least separation between two points to be distiguised by a microscope for light of `5000 Å` and electrons acclerated through 100V used as illuminating substance is __________ (neraly)

For the same objective, the ratio of least separation between two poin

1.	For the same objective, the ratio of least separation between two points to be distiguised by a microscope for light of `5000 Å` and electrons acclerated through 100V used as illuminating substance is __________ (neraly)
Answer» The limit of resolution of a microscope is `d = (lambda)/(2 sin theta)` where `2 theta` is the angle of cone of light rays entering the objective of the microscope. For light, `lambda_(1) = 5000 Å` For electrons accelerated through `100 V`, de Broglie wavelength, `lambda_(2) = (12.27)/(sqrt(100))Å = 1.227 Å`. ltbr? As `(2 sin theta)` is same in the two cases, therefore, `(d_(1))/(d_(2)) = (lambda_(1))/(lambda_(2)) = (5000)/(1.227) = 4075`

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