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For the value of x .if the distance between the points A(0,0)&B(x,-4) is 5 units? |
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Answer» By distance formula √(x2-x1)square+(y2-y1)square is equal to distance between two coordinateBy appling this formula we find the value of x become distance 5 units so;√(x-0)square+(-4-0)square = 5 units√X square+16=5Squaring both side we getX square + 16 = 25 X square= 25-16X square=9X=√9X=3? The formula used to find the distance between two points is{tex}d = \\sqrt{(x2-x1)^{2}+(y2-y1)^{2} } Where,d = distance = 5\\\\(x1, y1) = First set of points, i.e A= (0,0)\\\\(x2, y2) = Second set of points i.e B= (x,-4)d = \\sqrt{(x2-x1)^{2}+(y2-y1)^{2} } \\\\ 5 = \\sqrt{(x-0)^{2}+(-4-0)^{2} } \\\\\\\\5 = \\sqrt{(x)^{2}+(-4)^{2} }\\\\\\\\Squaring both sides\\\\\\\\25 = x^{2} + 16\\\\\\\\25-16 = x^{2}\\\\\\\\9 = x^{2}\\\\\\\\x = 3{/tex} |
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