For what value k, will the system of equations X+2y=53x+ky+15=0Have a

1.	For what value k, will the system of equations X+2y=53x+ky+15=0Have a unique solution
Answer» K is not equal to 6For all the values of k other than 6 The equation has a unique solution Here, a1=1,b1=2,c1=-5a2=3, b2=k, c2=15For a pair of linear equation to have a unique solution:a1/a2 not equal to b1/b2=1/3 not equal to 2/k ( solve this equation) ,we getK=6:.The value of k=6

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