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For what value of k+9 2k-1and 2k+7be the consecutive terms of an Ap |
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Answer» They are in ap therefore, common difference is same.(2k-1)-(k+9)=(2k+7)-(2k-1) 2k-1-k-9=2k+7-2k+1 K-10=8 K=8+10 K=18 Whose answer is correct? 2b = a+c. (K+9)+(2k+7) = 2(2 k+1). 3k+16 = 4k+2. -k = -14, k= 14 Sincecthey are in ap therefore there diff will be same 2k-1-(k+9)=2k+7-(2k-1)k=18 Just put identity : 2b= a+ c Answer: 14 4 6 a+c =2bk+9+2k+7=2×2k-13k+16=4k-4K=20 |
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