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For what value of `k`is the function`f(x)={(x^2-1)/(x-1)k,``,x!=1,x=1"c o n t i n u o u sa t"x=1?` |
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Answer» As `f(x)` is continuous at `x = 1`, `:. Lim_(x->0) f(x) = f(1).` `=>Lim_(x->0)(x^2-1)/(x-1) = k` `=>Lim_(x->0)((x+1)(x-1))/(x-1) = k` `=>Lim_(x->0)(x+1) = k` `=> 2 = k` `:.` For `k = 2`, given function will be continuous at `x = 1`. |
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