1.

For what value of `k`is the function`f(x)={(x^2-1)/(x-1)k,``,x!=1,x=1"c o n t i n u o u sa t"x=1?`

Answer» As `f(x)` is continuous at `x = 1`,
`:. Lim_(x->0) f(x) = f(1).`
`=>Lim_(x->0)(x^2-1)/(x-1) = k`
`=>Lim_(x->0)((x+1)(x-1))/(x-1) = k`
`=>Lim_(x->0)(x+1) = k`
`=> 2 = k`
`:.` For `k = 2`, given function will be continuous at `x = 1`.


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