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for what value of k will be k+9 2k-1 amd 2k+7 are the consecutive terms of an AP? |
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Answer» If these are consecutive terms then c.d should be same...2k-1-(k+9)=2k+7-(2k-1)2k-1-k-9=2k+7-2k+1k-10=8k=18 If given terms are in AP, then2k - 1 = (k + 9 + 2k + 7)/24k - 2 = 3k + 16k = 18 |
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