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For what value of k (x+1 ) is factor of p(x) kxsquare-x-4 |
| Answer» {tex}The given equation is kx^2-x-4= 0{/tex}{tex}It is given that(x+1 ) is a factor of the given equation.{/tex}{tex}x+1 = 0{/tex}{tex}x = -1{/tex}Substituting the value of x in the given equation, we get{tex}k(-1)^2- (-1)-4 = 0{/tex}{tex}k +1-4 = 0{/tex}{tex}k-3 = 0{/tex}k=3 | |