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For what value of p , are (2p-1) , 7 and 11p/2 three consecutive term of an AP |
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Answer» Thank you so much ? d=7-(2p-1)=7-2p+1=8-2pd=(11p/2)-7 =(11p-14)/2Therefore, 8-2p=(11p-14)/216-4p=11p-1416+14=11p+4p30=15p30/15=pp=2 |
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