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| 1. |
For what values of K, the roots of the equation x²+4k +K =0 are real |
| Answer» Compare x2\xa0+ 4x + k = 0 with ax2 + bx + c = 0a = 1 , b = 4, c = kSince roots of the equation x2\xa0+ 4x + k = 0 are real\xa0{tex}\\Rightarrow{/tex} b2 - 4ac = (4)2 - 4 (1) (k) = 16 - 4k\xa0{tex}\\geq{/tex}\xa00\xa0{tex}\\Rightarrow{/tex}\xa0k\xa0{tex}\\leq{/tex} 4 | |