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Form polynomial when alpha is 1/3 and beta is -3/2 |
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Answer» Given-α=1/3β=-3/2Sum of zeroes, α+β=(1/3) +(-3/2) =-7/6Product of zeroes, αβ= (1/3) *(-3/2) =-1/2We know that quadratic equation is of the form: x²-(α+β)x+(αβ)=0 x²-(-7/6) x+(-1/2) =0x²+7x/6-1/2=0Take the L. C. M. Of 1,6,2=6(6x²+7x-3) /6=06x²+7x-3=9 Sum (S) = 1/3 + (-3/2) = 2/6 - 9/6 = -7/6// Product (P) = 1/3 * -3/2 = -3/6// Polynomial p (x) = k(x^2 - Sx + P) = k (x^2 + 7/6x - 3/6) = k (6x^2 + 7x - 3)// |
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