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Formula to find sum of nth term of an AP.

Answer» n/2 [ 2a + (n-1) d ] for last term n/2 [ a+ l]
Sn=n/2(a+l)
An = n/2 +(a+(n_d))
Sn =n/2( 2a +(n -1 )d
Sn=n/2(2a+(n-1)d)
An= a+(n-1) * d


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