From a quadtric polynomial whose zeroes are 3-√3÷5 and 3+√3÷5.

1.	From a quadtric polynomial whose zeroes are 3-√3÷5 and 3+√3÷5.
Answer» Ans. Given : Zeroes of Polynomial are\xa0{tex}{3-\\sqrt 3\\over 5 }\\ and \\ {\\ 3+\\sqrt 3 \\over 5}{/tex}Sum of zeroes=\xa0{tex}{b\\over a}{/tex} =\xa0{tex}{3-\\sqrt 3\\over 5 } + {\\ 3+\\sqrt 3 \\over 5} = {6\\over 5}{/tex}=> {tex}{-b\\over a } = {30\\over 25}{/tex}\xa0Product of Zeroes = {tex}{c\\over a}{/tex}=\xa0{tex}{3-\\sqrt 3\\over 5 }\\times {\\ 3+\\sqrt 3 \\over 5} = {6\\over 25}{/tex}On comparing, we get = b = -30a = 25 and c = 6So now Required quadratic polynomial = 25x2 - 30x + 6\xa0\xa0

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