Given 15 cot a=8 find sin a and sec a

1.	Given 15 cot a=8 find sin a and sec a
Answer» 15 cot A = 8cotA= 8/15 = base/perpendicularbase= 8 and perpendicular = 15, So hypotenuse = √ base2\xa0+ perpendicular2\xa0= √82+152\xa0= √64+225 = √289 = 17base =8, perpendicular = 15 and hypotenuse = 17Sin A = perpendicular/ hypotenuse = 15/17Sec A = hypotenuse/ base = 17/8\xa0

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