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Given a= 7, a13= 35, find d and S13 |
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Answer» we know a=7 soa(n)=a+(n-1)da13=a+(13-1)dputting values35=7+(13-1)d35=7+12dSo d=28\\12d=7\\3S13=13\\2(a+l)=13\\2(7+35)=13\\2(42)=273 ans Hello mate!! a= 7a13= 35We know that, an= a+(n-1)da13= 7+(13-1)d35=7+12d35-7= 12d28= 12dTherefore, d= 28/12 d= 7/3Sn= n/2(2a+(n-1)d)s13= 13/2(2X 7+(13-1)7/3 =13/2(14+12X7/3) = 13/2(14+28) = 13/2X 42 = 13X 21 = 273 |
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