Given that 2x, 5,6-x are the first three terms of an AP, what will be

1.	Given that 2x, 5,6-x are the first three terms of an AP, what will be it\'s 10th term?
Answer» -19 a=2x and a2=5 So, d=a2-a=5-2x-(i) d=a3-a2= 6x-5 (ii) Comparing i and iiWe get, x=5/4So, d=5/2an=a+(n-1)da10=5+(10-1)(5/2)a10=5+45/2a10=55/2I thing you understood. common difference (d) = commonSo, 5 - 2x = 6 - x - 54 = xValue of x = 4.So, a = first term = 2x = 8d = - 3.a10 = a + 9d = 8 - 27 = -19Tenth term is - 17.

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