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| 1. |
Given that cos a =p/q, find the value of tan a |
| Answer» cos a=p/q{tex}\\begin{array}{l}\\sin\\;a=\\sqrt{1-\\frac{p^2}{q^2}}\\;\\\\=\\frac1q\\sqrt{q^2}-p^2\\\\So\\;\\tan\\;a=\\frac{\\sin\\;a}{\\cos\\;a}=\\frac{\\frac1q\\sqrt{q^2}-p^2}{\\displaystyle\\frac pq}\\\\=\\frac1p\\sqrt{q^2}-p^2\\end{array}{/tex} | |