Given that HCF(306,657)is 9,find lcm

1.	Given that HCF(306,657)is 9,find lcm
Answer» HCF × LCM= product of two no.s9× LCM= 306×657LCM= 22338 HCF(a & b)×LCM (a & b)=a×b9 × LCM(a & b) =306 × 6579 × LCM(a & b ) =201042LCM(a & b ) = 201042 ________ 9LCM(a & b)= 22338 2238

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