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Given the HCF (306, 657) = 9, find LCM (306, 657) |
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Answer» LCM×HCF=Product of two numbers LCM×9=306×657 LCM×9=201042LCM=201042÷9 LCM=22338 Let the LCM = x. HCF *LCM =Product of two numbers. 9*x=306*657 x=306*657/9 x=34*657 x=22,338 |
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