given triangle ABC is similar to triangle PQR, if AB/PQ= 1/3, then fin

1.	given triangle ABC is similar to triangle PQR, if AB/PQ= 1/3, then find ar(ABC)/ar(PQR)
Answer» ΔABC\xa0~ ΔPQRAB / PQ = BC / QR = AC / PR = 1 / 3and AB / PQ = BC / PQ = AC / PR = 1 / 3ar\xa0ΔABC / ar\xa0ΔPQR = (1 /\xa03)2\xa0= 1 / 9ar\xa0ΔABC / ar\xa0ΔPQR = 1 / 9

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