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Graph of velocity versus displacement of a particle moving in a straight line is as shown in figure. The acceleration of the particle is. A. constantB. increases linearly with `x`C. increases parabolically with `x`D. none of these |
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Answer» Correct Answer - B From the graph, velocity-displacement equation can be written as : `v = v_0 + alpha x` ….(1) Here `v_0` and `alpha` are positive constants. Differentiating (1) with respect to `x` we get `(dv)/(dx) = alpha = constant` Acceleration of the particle can be written as `a = v. (dv)/(dx) = (v_0 + alpha x) . alpha` `alpha- x` equation is a linear equation. Thus acceleration increases linearly with `x`. |
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