1.

Graph of velocity versus displacement of a particle moving in a straight line is as shown in figure. The acceleration of the particle is. A. constantB. increases linearly with `x`C. increases parabolically with `x`D. none of these

Answer» Correct Answer - B
From the graph, velocity-displacement equation can be written as :
`v = v_0 + alpha x` ….(1)
Here `v_0` and `alpha` are positive constants.
Differentiating (1) with respect to `x` we get
`(dv)/(dx) = alpha = constant`
Acceleration of the particle can be written as
`a = v. (dv)/(dx) = (v_0 + alpha x) . alpha`
`alpha- x` equation is a linear equation. Thus acceleration increases linearly with `x`.


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